## 判断是否闰年 1. .isLeapYear() > 返回
true
/
false
,
true
代表闰年,
false
代表非闰年。 ### 示例代码
javascript
java
csharp
php
python
go
var d = Solar.fromDate(new Date()); console.log(d.isLeapYear());
Solar d = Solar.fromDate(new Date()); System.out.println(d.isLeapYear());
Solar d = Solar.fromDate(new Date()); Console.WriteLine(d.isLeapYear());
$d = Solar::fromDate(new DateTime()); echo $d->isLeapYear()."\n";
d = Solar.fromDate(datetime.now()) print d.isLeapYear()
d := calendar.NewSolarFromDate(time.Now()) fmt.Println(d.IsLeapYear())
### 输出